n^2+79n-2400=0

Solution for n^2+79n-2400=0 equation:

n^2+79n-2400=0

a = 1; b = 79; c = -2400;
Δ = b2-4ac
Δ = 792-4·1·(-2400)
Δ = 15841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(79)-\sqrt{15841}}{2*1}=\frac{-79-\sqrt{15841}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(79)+\sqrt{15841}}{2*1}=\frac{-79+\sqrt{15841}}{2}
$